Question 1123884: Find the largest angle of a triangle where the larger is 20° greater than the smallest and the largest is twice the smallest angle. Found 2 solutions by MathLover1, MathTherapy:Answer by MathLover1(20849) (Show Source):
let’s the largest angle be , the larger , and the smallest angle
the sum is: ...............eq.1
if the larger is ° greater than the smallest, we have
....eq.2
if the largest is twice the smallest angle, we have
...............eq.3
go to ...............eq.1, substitute and from eq.1 and eq.3
....solve for °
go to ....eq.2, plug in °
go to ...............eq.3, plug in °
so, the largest angle of a triangle is °
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Find the largest angle of a triangle where the larger is 20° greater than the smallest and the largest is twice the smallest angle.
Let larger be L
Then smallest =
Also, larger (middle) =
We then get:
