Question 1120270: In the trapezoid CB=12, AB=30, CD=8 and angle B=30. What is the area? I should not use trigonometry to solve this problem. Answer by ikleyn(52784) (Show Source):
I will assume that in a trapezoid ABCD the segments AB and DC are parallel bases of the length of 30 and 8 units, respectively..
The lateral side BC is 12 units long.
Since the angle B is of 30 degrees, the height of the trapezoid from the vertex C drawn to the base AB is half of the length BC.
Hence, the altitude of the trapezoid is 6 units long.
Next, the area of a trapezoid (of ANY trapezoid) is the product of the altitude size by half of the sum of its bases.
In your case, the area of the trapezoid is A = = = 6*19 = 114 square units.
