SOLUTION: A square has a length of 4z and a width of 2w. If the perimeter is 32, find the value of w+z/w-z.

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Question 1119559: A square has a length of 4z and a width of 2w. If the perimeter is 32, find the value of w+z/w-z.
Answer by Alan3354(69443) About Me  (Show Source):
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A square has a length of 4z and a width of 2w. If the perimeter is 32, find the value of w+z/w-z.
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4z = 2w --- the sides of a square are equal
w = 2z
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(2z+z)/(2z-z) = 3z/z = 3