SOLUTION: I have a triangle. One of its angles is divided into two by a bisector. One of the two parts of the divided side is x and the total of two parts is 12. One of the other sides of th

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Question 1114771: I have a triangle. One of its angles is divided into two by a bisector. One of the two parts of the divided side is x and the total of two parts is 12. One of the other sides of the triangle is 9 and the other is not given. Find x.
If my explanation of the problem is not clear you can type angle bisector theorem practice into the google and click the first thing that came out. I don’t understand the 10th problem.
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
your triangle is right angle triangle
one leg is 12, the other leg is 9, so you use Pythagorean theorem to find the length of the hypotenuse c
c%5E2=12%5E2%2B9%5E2
c%5E2=144%2B81
c%5E2=225
c=sqrt%28225%29
c=15->the hypotenuse

since one leg is 12, the other leg is 9, on the leg (length12) one part x, than the other part is 12-x

now use proportion:
15%3A%2812-x%29=9%3Ax....solve for x
15x=%2812-x%299
15x=108-9x
15x%2B9x=108
24x=108
x=108%2F24
x=4.5