SOLUTION: ABCD is a square with side length x cm. M and N are the midpoints of AD and CD respectively. The midpoints and point B make a triangle which is the shaded area. Find the ratio of t

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Question 1111119: ABCD is a square with side length x cm. M and N are the midpoints of AD and CD respectively. The midpoints and point B make a triangle which is the shaded area. Find the ratio of the shaded to unshaded area.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
THE PICTURE:


THE FIFTH_GRADER'S SOLUTION:
If we connect M to the midpoint of BC,
and N to the midpoint of AB, we split the square into 4 smaller squares, each one being 1%2F4 of square ABCD.
Joining 2 of those small squares we would get a rectangle
that is 1%2F2 of square ABCD.
One of those 4 smaller squares
is divided into two equal triangular parts by diagonal MN,
so each of those two triangles is 1%2F8 of square ABCD.
Triangle MND is 1%2F8 of square ABCD.

The diagonal of a rectangle that is 1%2F4%2B1%2F4=1%2F2 of square ABCD
(such as diagonal MB),
divides the rectangle into two equal triangles.
Each of those triangles is 1%2F4 of square ABCD.
Triangle ABM is 1%2F4 of square ABCD, and so is triangle NCB.

The unshaded area is triangles ABM + NCB + MND, and amounts to
1%2F4%2B1%2F4%2B1%2F8=5%2F8 of the square.
So, the shaded area is
1-5%2F8=3%2F8 of the square.
Obviously the ratio of shaded area to unshaded area is
3%2F8%22%3A%225%2F8 or 3%3A5

THE EXPECTED SOLUTION is probably as follows
As ABCD is a square with side length x cm",
AB=BC=CD=AD=xcm .
As "M and N are the midpoints of AD and CD respectively",
AM=MD=DN=NC=x%2F2cm .
The unshaded area is made up of triangles ABM , NCB , and MND ,
so its total area is easy to calculate.
area%28ABM%29%22=%22%281%2F2%29%2AAB%2AAM%22=%22%281%2F2%29%2A%22%28+x%22%22cm+%29%22%22+%22%2A%22+%22%22%28%22x%2F2%22cm+%29%22%22=%22x%5E2%2F4cm%5E2 .
area%28NCB%29%22=%22%281%2F2%29%2ACB%2ANC%22=%22%281%2F2%29%2A%22%28+x%22%22cm+%29%22%22+%22%2A%22+%22%22%28%22x%2F2%22cm+%29%22%22=%22x%5E2%2F4cm%5E2 .
area%28MND%29%22=%22%281%2F2%29%2AMD%2AND%22=%22%281%2F2%29%2A%22%28%22x%2F2%22cm+%29%22%22+%22%2A%22+%22%22%28%22x%2F2%22cm+%29%22%22=%22x%5E2%2F8cm%5E2 .
unshadedarea%22=%22%28x%5E2%2F4%2Bx%5E2%2F4%2Bx%5E2%2F8%29cm%5E2%22=%22%285%2F8%29x%5E2cm%5E2

Calculating the shaded area as the area of triangle MNB may seem difficult,
However,
area%28MNB%29%22=%22shadedarea%22=%22area%28ABCD%29%22-%22unshadedarea
area%28ABCD%29%22=%22AB%2ABC%22=%22%22%28+x%22%22cm+%29%22%5E2%22=%22x%5E2cm%5E2
So, area%28MNB%29%22=%22shadedarea%22=%22x%5E2cm%5E2%22-%22%285%2F8%29x%5E2cm%5E2%22=%22%283%2F8%29x%5E2cm%5E2 .
The ratio of those two area values, both in cm%5E2 is
%28%283%2F8%29%29%2F%28%285%2F8%29%29%22=%22%283%2F8%29%2A%288%2F5%29%22=%22highlight%283%2F5%29 or highlight%283%3A5%29