SOLUTION: A farmer has 1080 feet of fencing and wants to enclose three adjacent rectangular corrals , if the area of the enclosed rectangle is 36,000 sq. ft., find the dimension of the three

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Question 1109893: A farmer has 1080 feet of fencing and wants to enclose three adjacent rectangular corrals , if the area of the enclosed rectangle is 36,000 sq. ft., find the dimension of the three enclosed area. length 540-2w and W
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I just answered this as problem # 1109885

I believe what is meant (but not really clearly specified) is shown in the sketch below:



Numbers/variables below are meant to be lengths in feet and areas in square feet,
but I am not writing the units repeatedly.
fencinglength%22=%222L%2B4W%22=%221080 ,
so 2L=1080-4W --> L=%281080-4W%29%2F2 --> L=540-2W .
The total surface area is
36000=%28540-2W%29%2AW
36000=540W-2W%5E2
2W%5E2-540W%2B36000=0
Dividing everything by 2, we get the simplified, equivalent equation
W%5E2-270W%2B18000=0
Factoring to solve that equation, we get
%28W-150%29%28W-120%29=0 --> system%28W=120%2C%22or%22%2CW=150%29 .
So, either system%28W=120%2CL=36000%2F120%29 --> system%28W=120%2CL=300%29 , or
system%28W=150%2CL=36000%2F150%29 --> system%28W=150%2CL=240%29
That gives us two possible answers for the dimensions of "the whole enclosed rectangle."
Either the whole enclosed area is 120ft wide by 300ft long, or it is
150ft wide by 240ft long.