Question 1086884: A rectangular swimming pool is twice as long as its width. A small concrete walkway is a constant 2 feet wide and has a area of 196 square feet. Find the dimension of the pool.Show solution
Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! It helps to draw this.
x=width
2x=length
area of pool is 2x^2.
the width of the pool + walkway is (x+4)(2x+4)=2x^2+12x+16
subtract from that 2x^2, the area of the pool, and the walkway has area 12x+16
This equals 196 ft^2
Therefore, 12x=180
x=15 feet
2x=30 feet
the pool is 450 ft^2, 15 x 30 feet
the whole complex is 19 x 34=646 ft^2.
The difference is 196 ft^2.
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