SOLUTION: What is the circumcenter of a triangle with a vertices of (2,4), (6,4), (2, 6)?

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Question 1065525: What is the circumcenter of a triangle with a vertices of (2,4), (6,4), (2, 6)?
Found 2 solutions by Fombitz, ikleyn:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Find the midpoints of the sides,
A(2,4)
B(2,6)
C(6,4)
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To find the midpoint, take the averages of the x and y values,
Midpoint of AC: (%282%2B6%29%2F2,%284%2B4%29%2F2)=(4,4)
Midpoint of AB: (%282%2B2%29%2F2,%284%2B6%29%2F2)=(2,5)
Midpoint of BC: (%282%2B6%29%2F2,%286%2B4%29%2F2)=(4,5)
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Now find the lines through mAC and B(line 1), mAB and C(line 2), and mBC and A(line 3).
First find the slope, then use the point slope form of a line,
I'll use the designation 1, 2, 3 for the lines as defined in the previous sentence.
Line 1:
m%5B1%5D=%284-6%29%2F%284-2%29=-2%2F2=-1
y-4=-1%28x-4%29
y-4=-x%2B4
y%5B1%5D=-x%2B8
Line 2:
m%5B2%5D=%285-4%29%2F%282-6%29=1%2F%28-4%29=-1%2F4
y-5=-%281%2F4%29%28x-2%29
y-5=-x%2F4%2B1%2F2
y=-x%2F4%2B1%2F2%2B10%2F2
y%5B2%5D=-x%2F4%2B11%2F2
Now that we have two lines, we can calculate their intersection (which is the circumcenter),
-x%2B8=-x%2F4%2B11%2F2
-4x%2B32=-x%2B22
-3x=-10
x%5BCC%5D=10%2F3
and
y=-10%2F3%2B8
y=-10%2F3%2B24%2F3
y%5BCC%5D=14%2F3
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Answer by ikleyn(52780) About Me  (Show Source):
You can put this solution on YOUR website!
.
This triangle is RIGHT-ANGLED.

The circumcenter of ANY right-angled triangle lies in the midpoint of its hypotenuse.

The hypotenuse has vertices (6,4) and (2,6).

Its midpoint is x = (6+2)/2 = 8/2 = 4  and  y = (4+6)/2 = 10/2 = 5.

Answer. The circumcenter is the point with the coordinates (x,y) = (4,5).

SOLVED.


For the fact that a circumcenter of a right-angled triangle is the midpoint of its hypotenuse, see the lesson
    - Median drawn to the hypotenuse of a right triangle
in this site.


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