SOLUTION: a rectangular building whose depth is twice its frontage is divided into two parts by a portion that is 20 ft from and parallel to the front wall.If the rear portion of the buildin
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Question 1063412: a rectangular building whose depth is twice its frontage is divided into two parts by a portion that is 20 ft from and parallel to the front wall.If the rear portion of the building contains 3500 ft^2 find the dimwnsions of the building. Answer by KMST(5328) (Show Source):
You can put this solution on YOUR website! = frontage of the building, in feet.
So, the area of the rear portion of the building, in square feet
is represented by ,
and our equation is .
Solving that equation gives us .
so the building's frontage is ,
and so since it's depths is twice its frontage,
the building's depth is .
