Question 1062706: How much water should be mixed to a 500 mL of 30% solution of alcohol to have a resulting concentration of 20%? Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
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How much water should be mixed to a 500 mL of 30% solution of alcohol to have a resulting concentration of 20%?
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Your equation is
= 0.2,
where W is unknown amount (volume) of water in mL.
The equation is equivalent to
0.3*500 = 0.2*(500 + W).
Simplify and solve for W.
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