SOLUTION: An engineer wants to build a rectangular foundation that is divided into 5 sections as shown in the figure below. If she uses 5000 linear feet of material for the division, what is
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: An engineer wants to build a rectangular foundation that is divided into 5 sections as shown in the figure below. If she uses 5000 linear feet of material for the division, what is
Log On
Question 1055871: An engineer wants to build a rectangular foundation that is divided into 5 sections as shown in the figure below. If she uses 5000 linear feet of material for the division, what is the maximum area enclosed by the foundation? Round your result to the nearest square foot. Width = x Length = (5000-6x)/2 Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
An engineer wants to build a rectangular foundation that is divided into 5 sections as shown in the figure below.
If she uses 5000 linear feet of material for the division, what is the maximum area enclosed by the foundation?
Round your result to the nearest square foot. Width = x Length = (5000-6x)/2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Since width W = x and Length L = = , the area is the product W*L
A = W*L = = .
This quadratic function has a maximum at
x = = = .
And this maximum value is = = = = 52.083*10^4 square feet.