SOLUTION: A farmer enclosed a rectangular field with 500 m of fencing. (Area of 15400 m sq). A. Determine the dimensions of the field? B. What would the dimensions of the field be if he

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Question 1042964: A farmer enclosed a rectangular field with 500 m of fencing. (Area of 15400 m sq).
A. Determine the dimensions of the field?
B. What would the dimensions of the field be if he wanted to maximize the area? Prove algebraic ally.

Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
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A farmer enclosed a rectangular field with 500 m of fencing. (Area of 15400 m sq).
A. Determine the dimensions of the field?    

   L + W = 500%2F2 = 250.   (1)
   L*W   = 15400.         (2)

   Express L = 250 - W from (1) and substitute into (2). You will get

   (250-W)*W = 15400.

   Simplify and solve this quadratic equation.

   W%5E2+-+250W+%2B+15400 = 0.

   W = %28250+%2B-+sqrt%28250%5E2+-+4%2A15400%29%29%2F2 = %28250+%2B-+30%29%2F2.

   We select lesser of the two roots W = 110, leaving the greater root for L = 140.

   Answer. The dimensions are 140 m and 110 m.



Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

A farmer enclosed a rectangular field with 500 m of fencing. (Area of 15400 m sq).
A. Determine the dimensions of the field?
B. What would the dimensions of the field be if he wanted to maximize the area? Prove algebraic ally.
Dimensions: highlight_green%28matrix%281%2C5%2C+110%2C+m%2C+by%2C+140%2C+m%29%29
To maximize area, the field MUST be a square, with one of its sides being: highlight_green%28matrix%281%2C4%2C+500%2F4%2C+or%2C+125%2C+m%29%29