SOLUTION: What is the fewest number of tacks needed to hold up 41 pictures of the same size so that each picture can be seen and each corner is tacked? (Suggestion: Use strategies: making a
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: What is the fewest number of tacks needed to hold up 41 pictures of the same size so that each picture can be seen and each corner is tacked? (Suggestion: Use strategies: making a
Log On
Question 1042074: What is the fewest number of tacks needed to hold up 41 pictures of the same size so that each picture can be seen and each corner is tacked? (Suggestion: Use strategies: making a drawing and solving a simpler problem.)
I have gotten 84 as an answer and it is wrong. Please help! Answer by solver91311(24713) (Show Source):
This is a problem in minimizing a perimeter given an area. For a rectangular figure, the smallest perimeter for a given area is a square. So, in order to minimize the number of tacks, you need to arrange the pictures in a shape as close to a square as possible. 36 of the pictures make a 6 X 6 square, which takes 7 rows of 7 tacks to hit every corner, then you make another row of 5 pictures along any side of the 6 X 6 array and you add another 6 tacks. Total of 55.
John
My calculator said it, I believe it, that settles it
