SOLUTION: The length of a field is 6m greater than its width .if the perimeter must not exceed 80m, calculate the greatest value for its width

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Question 1037435: The length of a field is 6m greater than its width .if the perimeter must not exceed 80m, calculate the greatest value for its width

Answer by thesvw(77) About Me  (Show Source):
You can put this solution on YOUR website!
Let the width be W. So length is W+6.
Now for a maximum perimeter, we can take 80.
80+=+2W+%2B2%28W%2B6%29%0D%0A%0D%0A80+=+4W+%2B+12%0D%0A%0D%0A68%2F4+=+W%0D%0A%0D%0AW+=+17 m