SOLUTION: The length of a rectangle is 6m greater than its width. If the perimeter must not exceed 80m, calculate the greatest value for its width.

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Question 1037433: The length of a rectangle is 6m greater than its width. If the perimeter must not exceed 80m, calculate the greatest value for its width.
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let w be the width, l be length:
2w+2l=p, perimeter
2w+2(w+6)=80
4w+12=80
w=17
The greatest width possible is 17m!!!!!!!!!!!!!!!