Question 1035557: Hi tutors, hopefully you ca help with this grade 3 math makes sense book word problem..:)
The title: Comparing Area and Perimeter
Ingrid bought 12 units of fencing to enclose her yard. What might the area of her yard be?
Give as many different answers as you can.
Found 3 solutions by josgarithmetic, MathTherapy, ikleyn:
Answer by josgarithmetic(39617)   (Show Source):
You can put this solution on YOUR website! Too open. Choose any value you want between 0 and 12 as a divisor. Use some values that are practical. How about 2?  and d is the other dimension for the rectangular region to be fenced; but only an example.
To continue with this example, 2 units by d units, the area would be  square units.
Grade 3 level of basic mathematics question?
The question NEEDS to include what shape is this yard to be fenced. I assumed a rectangle. An example was chose as one direction being 2, so this would be for two opposites sides of the assumed rectangle. These account for length of 4 length units. You know the distance around the yard must be 12 units, leaving 8 more units to be accounted. The other two opposite sides would together be this 8 units, so because there are two of them, the 8 is cut into two equal parts, so 4 units. Area would be  square units.
The number of combinations you can find can be many. I chose 2 because it is a WHOLE number, so this should be understandable for grade 3 person, but grade 3 is probably also the time when a student starts to learn about fractions. You could choose a mixed number value greater than 0 but less than 12, and analyze the combination starting with the chosen value.
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Hi tutors, hopefully you ca help with this grade 3 math makes sense book word problem..:)
The title: Comparing Area and Perimeter
Ingrid bought 12 units of fencing to enclose her yard. What might the area of her yard be?
Give as many different answers as you can.
12 units represents the PERIMETER of the fence
As perimeter = 2 times length + 2 times width, we can say that:
P = 2(L + W)
12 = 2(L + W)
2(6) = 2(L + W)
2 = 2, so 6 = L + W, and therefore,  . Choose any number for W (the width) and the length will be 6 minus that value.
Multiply the width by the length and you have the area of the yard.
Choosing a value of 1 for width
For example, if I choose 1 for the width, then the length is: 6 - 1 = 5, and the area is: 1(5), or 
Choosing a value of 3 for width
For example, if I choose 3 for the width, then the length is: 6 - 3 = 3, and the area is: 3(3), or 
Choosing a value of 4 for width
For example, if I choose 4 for the width, then the length is: 6 - 4 = 2, and the area is: 4(2), or 
Answer by ikleyn(52781)  (Show Source):
You can put this solution on YOUR website! .
It is nowhere said in the condition that Ingrid wants to install 4-sided fence.
What if she wants to install 3-sided fence to constrain the area adjacent to her home?
This is a typical example of BADLY DESIGNED, BADLY TARGETED and BADLY FORMULATED problem.
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