SOLUTION: The length of a rectangle is 1 cm longer than its width. If the diagonal of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?

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Question 103473: The length of a rectangle is 1 cm longer than its width. If the diagonal
of the rectangle is 4 cm, what are the dimensions (the length and the width) of the rectangle?
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
LENGTH=W+1
WIDTH=W
W^2+(W+1)2=4^2
W^2+W^2+2W+1=16
2W^2+2W+1-16=0
2W^2+2W-15=0 USING THE QUADRATIC EQUATION:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
W=(-2+-SQRT[2^2-4*2*-15])/2*2
W=(-2+-SQRT[4+120])/4
W=(-2+-SQRT124)/4
W=(-2+-11.14)/4
W=(-2+11.14)/4
W=9.14/4
W=2.28 ANSWER.
W=-2-11.14/4
W=-13.14/4
W=-3.28 ANSWER.