SOLUTION: Level 3: The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the len

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Question 1028071: Level 3: The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room.
Which equations can be used to solve for y, the length of the room? Check all that apply.

750 – y(y – 5) = 0

y(y + 5) = 750

y(y – 5) + 750 = 0

(y + 25)(y – 30) = 0

y2 – 5y = 750
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
y= length of the room, in feet
y-5= width of the room, in feet
y%28y-5%29=750= area of the room in square feet
One equation that can be used to solve for y is y%28y-5%29=750 ,
but there is an infinite number of equivalent equations.
y%28y-5%29=750<-->750=y%28y-5%29<-->highlight%28750-y%28y-5%29=0%29
(We could also get y%28y-5%29-750=0<-->y%28y-5%29=750 ).
y%28y-5%29=750<-->highlight%28y%5E2-5y=750%29
y%28y-5%29=750<-->y%5E2-5y=750<-->y%5E2-5y-750=0<-->highlight%28%28y%2B25%29%28y-30%29=0%29