SOLUTION: the medians of a right triangle that are drawn from the vertices of the acute angles have lengths of 2 square root 13 and square root 73. find the lengths of the hypotenuse.

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Question 1019325: the medians of a right triangle that are drawn from the vertices of the acute angles have lengths of 2 square root 13 and square root 73. find the lengths of the hypotenuse.
Answer by ikleyn(52778) About Me  (Show Source):
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The medians of a right triangle that are drawn from the vertices of the acute angles have lengths of 2 square root 13 and square root 73. Find the lengths of the hypotenuse.
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Answer. The length of the hypotenuse is 10 units.

Solution

We will use this property of a median, which is valid for any triangle:

  In a triangle with the sides a, b and c, the median drawn to the side c has the length m%5Bc%5D = sqrt%28%282a%5E2+%2B+2b%5E2+-+c%5E2%29%2F2%29.

See the lesson The length of a median of a triangle in this site.

Next, let us apply the property to a right-angled triangle, whose legs are a and b units long and the hypotenuse is c units long.

For the medians  m%5Ba%5D  and  m%5Bb%5D  drawn to the legs a and b respectively, we will have

m%5Ba%5D%5E2 = %282b%5E2+%2B+2c%5E2+-+a%5E2%29%2F4,  m%5Bb%5D%5E2 = %282a%5E2+%2B+2c%5E2+-+b%5E2%29%2F4. 

Therefore,

m%5Ba%5D%5E2 + m%5Bb%5D%5E2 = %282b%5E2+%2B+2c%5E2+-+a%5E2%29%2F4 + %282a%5E2+%2B+2c%5E2+-+b%5E2%29%2F4 = %282b%5E2+%2B+2c%5E2+-+a%5E2+%2B+2a%5E2+%2B+2c%5E2+-+b%5E2%29%2F4 = %28a%5E2+%2B+b%5E2+%2B+4c%5E2%29%2F4.

Since for the right-angled triangle a%5E2+%2B+b%5E2 = c%5E2, you can rewrite the above equality in the form

m%5Ba%5D%5E2 + m%5Bb%5D%5E2 = %28c%5E2+%2B+4c%5E2%29%2F4 = %285%2F4%29%2Ac%5E2.

Now substitute the given data  m%5Ba%5D = 2%2Asqrt%2813%29  and  m%5Bb%5D = sqrt%2873%29. You will get

%285%2F4%29c%5E2 = 4%2A13+%2B+73 = 125.

It implies  c%5E2 = %284%2F5%29%2A125 = 100.

Hence, c = 10.

The problem is solved.