SOLUTION: An ice rink is in the shape of a rectangle with semicircular ends. The straight
sides are 60m long and 30m apart. It is to be filled to a depth of 10cm with
ice. Calculate ho
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-> SOLUTION: An ice rink is in the shape of a rectangle with semicircular ends. The straight
sides are 60m long and 30m apart. It is to be filled to a depth of 10cm with
ice. Calculate ho
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Question 1017389: An ice rink is in the shape of a rectangle with semicircular ends. The straight
sides are 60m long and 30m apart. It is to be filled to a depth of 10cm with
ice. Calculate how many cubic metres of ice will be needed.
You can put this solution on YOUR website! The volume of ice needed is the area of the rink times the depth, 0.1 m.
The rink is a 60m by 30m rectangle. That area is 1800 m^2.
The semi-circles at each end become a full circle whose radius is 15m
Its area is A = (pi)r^2 = (3.14)(15^2) = 706.5 m^2
Thus the total area of the rink is
1800 + 706.5 = 2506.5 m
Now multiply that by the depth (0.1m) and we get
V = 2506.5 * 0.1 = 250.65 cubic meters of ice.
You can put this solution on YOUR website! It helps to draw this.
There is a rectangle with dimensions 60 m X 30 m.
The two semicircular ends form one circle with diameter 30 m, radius 15 m.
The area is 1800 m^2+225*pi m^2, the last being the area of a circle.
The total area is 2506.85 m^2, after multiplying by pi.
This is to be multiplied by 10 cm=0.1 m
The units will be m^3.
250.86 m^3 of ice are needed after multiplying by 0.1
