Question 1016737: The singles court in badminton is 27 feet longer than it is wide.If its perimeter is 122 feet, what are the length and the width. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! .
W=width; L=length=W+27ft
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P=2(L+W)
122ft=2(L+W)
61ft=L+W
61ft=(W+27ft)+W
61ft=2W+27ft
34ft=2W
17ft=W
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ANSWER 1: The width is 17 feet.
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L=W+27ft=17ft+27ft=44ft
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ANSWER 2: The length is 44 feet.
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CHECK:
P=2(L+W)
122ft=2(44ft+17ft)
122ft=2(61ft)
122ft=122ft
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