Question 101649: Find the three angles of a triangle if the second angle is twenty more than the first angle, and the third angle is twice the frist angle. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Let’s name the angles A, B, and C.
Then you know that B = A + 20 and C = 2(A).
Finally since it’s a triangle, the sum of all of the angles equals 180 or A + B + C = 180.
Substitute the values of B and C from above and you get :
A + B + C = 180
A + (A+20) + 2A = 180
4A + 20 = 180
4A + 20 – 20 = 180 – 20
4A = 160
A = 40
Substitute back into your equations for B and C.
B = A + 20
B = 40 + 20
B = 60
C = 2A
C = 2(40)
C = 80
A = 40
B = 60
C = 80