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Finding the distanse from a point in 3D to a plane
Problem 1
Point P is at 10 cm distance from the vertices of a triangle with sides 4, 5, and 6 units long.
Find the distance from point P to the plane of the triangle.
Solution
Consider the plane of the triangle and the sphere of the radius R = 10 cm with the center at the point P.
This plane cuts the sphere and the triangle lies in/at the cutting section.
Now what you need is to find the radius "r" of the circle circumscribed about the triangle.
Then the distance from the point P to the plane is
d = . (1)
For the radius of the circle circumscribed about the triangle, there is the formula
r = , (2)
where a, b, and c are the triangle's side dimensions and A is its area.
See the lesson Proof of the formula for the radius of the circumscribed circle in this site.
To calculate the area, use the Heron's formula
A = (where s is semi-perimeter) = = = 9.922 cm^2 (approximately).
Then according (2) r = = 3.024 cm (approximately).
Then the distance from P to the plane (which is the value under the question) is
d = = 9.532 cm.
My other lessons on Miscellaneous advanced Geometry problems in this site are