Question 986160: A store sells tents, sleeping bags, and camp stools. A customer buys a tent, 3 sleeping bags, and 5 camp stools for $213. The price of the tent is 7 times the cost of a camp stool. The cost of a sleeping bag is $26 more than the cost of a camp stool. Find the cost of each item.
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! t = price of tent
s = price of sleeping bag
c = cost of camp stool
t = 7c {price of tent is 7 times cost of camp stool}
s = c + 26 {cost of sleeping bag is 26 more than cost of camp stool}
t + 3s + 5c = 213 {buys a tent 3 sleeping bags and 5 camp stools for $213}
7c + 3(c + 26) + 5c = 213 {substituted 7c for t and (c + 26) in for s, into t + 3s + 5c = 213}
7c + 3c + 78 + 5c = 213 {used distrbutive property}
15c + 78 = 213 {combined like terms}
15c = 135 {subtracted 78 from each side}
c = 9 {divided each side by 15}
t = 7c {first equation}
t = 7(9) {substituted 9, in for c, into first equation}
t = 63 {multiplied}
s = c + 26 {second equation}
s = 9 + 26 {substituted 9, in for c, into second equation}
s = 35 {added}
$9 = cost of camp stool
$63 = cost of tent
$35 = cost of sleeping bag
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