Question 982190: Find two numbers such that:
1. Their difference is 13 and their product is -40
2. Their sum is 2 and their difference is 128
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find two numbers such that:
1. Their difference is 13 and their product is -40
x-y = 13
xy = -40
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Substitute for "x" and solve for "y":
(y+13)y = -40
y^2 + 13y + 40 = 0
(y-5)(y-8) = 0
If y = 5, x = -8
If y = 8, x = -5
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2. Their sum is 2 and their difference is 128
x + y = 2
x - y = 128
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2x = 130
x = 65
y = 63
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Cheers,
Stan H.
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