Question 961452: I am having a bit of trouble with this question, I've set it up, but I can't seem to get the correct answer.
A phone company offers two monthly charge plans. In Plan A, the customer pays a monthly fee of $6.60 and then an additional 8 cents per minute of use. In Plan B, there is no monthly fee, but the customer pays 9 cents per minute of use.
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! So, I think your question is incomplete. Are you supposed to 1)find out at what point one service is cheaper than the other, or 2)does the problem ask you "if you use x minutes, which one is cheaper?" Since I have no information for 2), I'll give you the answer to 1): at how many minutes does one plan become cheaper than the other.
6.60+.08x = .09x Subtract .08 from both sides:
6.60= .01x Divide both sides by .01
660= x At 660 minutes of usage, both plans would cost you exactly the same.
A: 6.60+.08(660)= 6.60+52.08= 59.40
B: .09(660)= 59.40
From 660 minutes on, the .08 plan is cheaper. Try it, in A: and B: above, substitute 660 with a higher number, any number you like. Maybe just one minute more, like 661: 6.60+.08(661)= 59.48 and .09(661)= 59.49 From here, the more minutes the cheaper plan A will be.
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