Question 928658: Bradley has $25,000 that he wants to invest. He invests it in accounts paying 12%, 7%, and 6% simple interest. The account paying 12% is higher-risk account, so he wants the amount in that account to be half of the amount he has in the account paying 6% simple interest. If his annual interest is $1945, how much is invested at each rate?
Answer by ewatrrr(24785) (Show Source):
You can put this solution on YOUR website! .12x + .07(25000 - 3x) + .06(2x) = 1945
.12x - (.21x) + .12x = 1945 - 1750
.03x= 195
x = $6500, amount at 12%
2x = $13,000, amount at 6%
= $5,500, amount at 7%
And..checking
Sum = $25,000
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