SOLUTION: Water initially at 190°F. is left in a room of temperature 70°F to cool. After t minutes, the temperature T of the water is given by T(t) = 70 + 120e – 0.096 t
Find the temperat
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-> SOLUTION: Water initially at 190°F. is left in a room of temperature 70°F to cool. After t minutes, the temperature T of the water is given by T(t) = 70 + 120e – 0.096 t
Find the temperat
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Question 849960: Water initially at 190°F. is left in a room of temperature 70°F to cool. After t minutes, the temperature T of the water is given by T(t) = 70 + 120e – 0.096 t
Find the temperature of the water 10 minutes after it is left to cool. (Round to the nearest degree.) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Water initially at 190°F. is left in a room of temperature 70°F to cool. After t minutes, the temperature T of the water is given by T(t) = 70 + 120e – 0.096 t
Find the temperature of the water 10 minutes after it is left to cool. (Round to the nearest degree.)
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I think it's ?
T(10) = 116 degs
