SOLUTION: Frank makes and sells small picture frames. His revenue from sales can be represented as R=$13.60x for x frames sold. The cost of making the frames can be represented as C=$5.80x

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Frank makes and sells small picture frames. His revenue from sales can be represented as R=$13.60x for x frames sold. The cost of making the frames can be represented as C=$5.80x       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 846746: Frank makes and sells small picture frames. His revenue from sales can be represented as R=$13.60x for x frames sold. The cost of making the frames can be represented as C=$5.80x +$120 for x frames made. What is the minimum number of frames Frank must sell in order for his revenue to be greater than his costs.
Please help, I can't wrap my head around this one. Thanks, Karl
pistolpest2000@yahoo.com
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If profit = +P+, then +P+=+R+-+C+
+P+=+13.6x+-+%28+5.8x+%2B+120+%29+
+P+=+13.6x+-+5.8x+-+120+
+P+=+7.8x+-+120+
Make the profit zero, which means +R+=+C+
+7.8x+-+120+=+0+
+7.8x+=+120+
+x+=+15.385+
You can't have a fraction of a frame,
so the profit is zero when Frank sells
15 frames, and he begins to make a
profit when he sells 16 frames
---------------
check:
+P+=+7.8x+-+120+
+0+=+7.8%2A15.385+-+120+
+0+=+120.003+-+120+
+0+=+.003+
close enough