SOLUTION: A radiator contains 8 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 45% antifreeze solution? (Round your answer to

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Question 838986: A radiator contains 8 liters of a 25% antifreeze solution. How much should be drained and replaced with pure antifreeze to produce a 45% antifreeze solution? (Round your answer to two decimal places.)
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
v = amount of liters to drain and replace

%288%2A25-25v%2B100v%29 represents the amount of antifreeze material resulting in the radiator. A factorization will be useful: 200%2B%28100-25%29v.

%28200%2B%28100-25%29v%29%2F8=45
highlight%28%28200%2B75v%29%2F8=45%29
Solve for v.
-
200%2B75v=360
75v=160
v=2.133333... liters to remove and replace
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About 2 liters 130 mililiters
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