SOLUTION: A girl bought mangoes at P7.50 each. There were two types of mangoes: good ones and not so good ones. She sold the good ones at P7.90 each and the not-so-good ones at P7.70 each. I

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: A girl bought mangoes at P7.50 each. There were two types of mangoes: good ones and not so good ones. She sold the good ones at P7.90 each and the not-so-good ones at P7.70 each. I      Log On

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Question 828202: A girl bought mangoes at P7.50 each. There were two types of mangoes: good ones and not so good ones. She sold the good ones at P7.90 each and the not-so-good ones at P7.70 each. If she earned P34, how many mangoes did she buy?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
x is how many good mangos
y is how many not so good..

Girl spent %28x%2By%29%2A7.5 P of money for the mangos.
Her revenue was 7.90x%2B7.70y.

Her earning were the profit: 7.9x%2B7.7y-%28x%2By%29%2A7.5=34 P

You do not have enough described information to find x or y or their sum. The problem description only allows for one equation in two unknown variables.




-----Pushing a little further------
7.9x-7.5x%2B7.7y-7.5y=34
0.4x%2B0.2y=34
0.2x%2B0.1y=17
2x%2By=170
highlight%28y=-2x%2B170%29
You can accept any or all positive whole number ordered pairs for x and y.
This may be anything from 85 good mangos and 0 bad mangos; to 0 good mangos and 170 bad mangos.