SOLUTION: (1) The total cost of 12kg of apples and 24kg of oranges is #2160, and the total cost of 24kg of apples and 12kg of oranges is #1800. Find the total cost of 3kg of apple and 10kg o

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: (1) The total cost of 12kg of apples and 24kg of oranges is #2160, and the total cost of 24kg of apples and 12kg of oranges is #1800. Find the total cost of 3kg of apple and 10kg o      Log On

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Question 825088: (1) The total cost of 12kg of apples and 24kg of oranges is #2160, and the total cost of 24kg of apples and 12kg of oranges is #1800. Find the total cost of 3kg of apple and 10kg of oranges.
(2) A man's income from interest is #500. He doubles his investment and also gets an increase of 5% in wages And his Income increases to #800. What was his original income separating in terms of interest(I) and wages(W)
(3) A student scores 5x marks In the first exam papers and x+10 marks in the second. He came second in the exam. The first student scoring a total of 118 marks. Find the range of value of x.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The q#1 is a simple two-variable system of equation exercise. The #2 and #3? Maybe not.

#1:

We want variables for price of oranges and price of apples. Pounds(money unit) per kilogram.
x = apple price
y = orange price

12x%2B24y=2160 and 24x%2B12y=1800
'
x%2B2y=180 and 2x%2By=150

2x%2B4y=360, and 2x%2By=150 so subtract the second equation from the first equation.
%282x%2B4y%29-%282x%2By%29360-150
3y=210
highlight%28y=70%29, pounds per kilogram oranges.
x=180-2y=180-2%2870%29=highlight%2840%29 , pounds per kilogram apples.
'
Use these x and y to answer your question.

#3:
You are not clear about, "student" and "first student". You might mean, a student scored 5x and x+10. The only student who scored better received 118 for marks. This must mean that the 118 marks is greater than the 5x+x+10 marks.

5x%2Bx%2B10%3C118, and naturally, x%3E0;
6x%3C108, and x%3E0;
highlight_green%280%3Cx%3C18%29
As a practical feel, I'd imagine x must really be 1 or more, so a better choice about x is to say:
highlight%281%3C=x%3C18%29; but that choice may be just arbitrary.