SOLUTION: an object is dropped from 38 feet below the tip of the pinnacle atop a 362-ft tall building. the height h of the object after t seconds is given by the equation h= -16t^2+324. find

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: an object is dropped from 38 feet below the tip of the pinnacle atop a 362-ft tall building. the height h of the object after t seconds is given by the equation h= -16t^2+324. find      Log On

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Question 823896: an object is dropped from 38 feet below the tip of the pinnacle atop a 362-ft tall building. the height h of the object after t seconds is given by the equation h= -16t^2+324. find how many seconds pass before the object reaches the ground
? seconds pass before the object reaches the ground

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
h= -16t^2+324
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It hits when h = 0
-16t%5E2+%2B+324+=+0
Solve for t.