Question 802: If a vehicle was purchased for $12590.00, which was 20% off the original price, what was the original price? Found 3 solutions by pushpaharan, JamieL38, longjonsilver:Answer by pushpaharan(47) (Show Source):
You can put this solution on YOUR website! let original price = x
then if you reduce the price by 20%, the selling price = x- 20% of x
= x-0.2x
=0.8x = $12590
therfore x = $12590 / 0.8
= $15737.50
;-)
You can put this solution on YOUR website! Since the vehicle was purchased for 20% off the original price, the buyer paid 80% of the original price. Let x represent the original price.
Our equation becomes:
80%*x=12590
The vehicle's original price was $16187.50.
Another way to solve this same problem is to subtract 20% of the original price from the original price. The equation would look like this:
x-20%*x=12590
You'll notice it's pretty much the same problem as above when you start working through it. You'll get the same answer.
You can put this solution on YOUR website! the other answer is so badly wrong, i cannot believe it!
Let x = original price.
The long way (and safest way) is as follows:
Find what 20% of the original is.
Subtract this from the original
that answer is equal to 12590
so...what is 20% of x?...answer is (20/100)*x which is 0.2x
original minus the 20% discount is (x - 0.2x) which is 0.8x and this is equal to the price of $12590
so 0.8x = 12590 --line A
therefore x = 12590/0.8
x = 15737.50
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Quick method.... a % reduction is less than 1 at line A...10% reduction would be 0.9, 25% reduction would be 0.75 etc
An increase would therefore be greater than 1, eg 10% increase is 1.10. 3% increase is 1.03 (NOT 1.3)
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jon
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