SOLUTION: A group of fishermen rented a boat for PhP2400.00. Two of the men withdrew from the party and as result, the share of each of those remaining was increased by 100. How many were in

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Question 771740: A group of fishermen rented a boat for PhP2400.00. Two of the men withdrew from the party and as result, the share of each of those remaining was increased by 100. How many were in the original group?

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39623) (Show Source):
You can put this solution on YOUR website!
n fishermen in the original group of fishermen. Each would pay PhP.
"Two men withdrew", then n-2 are in the adjusted group. Each would pay PhP.

The adjusted group forces each member to pay MORE than the each member of the original group; 100 PhP difference and

Multiply both sides by n(n-2)

*__________(mistake WAS found but now fixed)

Resorting to General Solution to Quadratic Formula but omitting some steps here,... .
,

EIGHT fishermen originally.

Answer by MathTherapy(10555) (Show Source):
You can put this solution on YOUR website!

A group of fishermen rented a boat for PhP2400.00. Two of the men withdrew from the party and as result, the share of each of those remaining was increased by 100. How many were in the original group?

Let original amount in group be G
Then each original member had to pay
With 2 men withdrawing, that leaves G � 2 men
New amount each will pay =
As each member from new group pays $100 more, then:

2,400G � 100G(G � 2) = 2,400(G � 2) ------- Multiplying by LCD, G(G � 2)

------ Factoring out GCF, 100

(G - 8)(G + 6) = 0

G, or original amount in group = OR G = - 6 (ignore)

You can do the check!!

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