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Question 678245:
Found 2 solutions by pmatei, MathTherapy:
Answer by pmatei(79) About Me  (Show Source):
You can put this solution on YOUR website!
If x is the amount she invested at 5%, than 5x (5 times x) is the amount she invested at 8%.
x%2A%285%2F100%29 is what she earns from the 5% investment, and 5x%2A%288%2F100%29 is what she earns from the 8% investment. Thus you can write:
x%2A%285%2F100%29+%2B+5x%2A%288%2F100%29+=+3150
x%2F20+%2B+8x%2F20+=3150
9x%2F20+=+3150
x+=+3150%2A20%2F9
x+=+7000
Thus the woman invested $7,000 at 5% and $35,000 at 8%.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

A woman invested 5 times as much at 8% as she did at 5%. The total amount of interest she earns in 1 year from both accounts is $3,150. How much did she invest at each rate?

Let amount invested at 5% be F
Then amount invested at 8% = 5F
Therefore, .05F + .08(5F) = 3,150
.05F + .4F = 3,150
.45F = 3,150
F, or amount invested at 5% = 3150%2F.45, or $highlight_green%287000%29

Amount invested at 8% = 5(7,000), or $highlight_green%2835000%29

You can do the check!!

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