SOLUTION: There were 36 nickels, dimes and quarters whose value was $6. If there were three times as many quarters as nickels, how many coins of each kind were there?

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Question 67296This question is from textbook An Incremental Development
: There were 36 nickels, dimes and quarters whose value was $6. If there were three times as many quarters as nickels, how many coins of each kind were there?
 This question is from textbook An Incremental Development

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
N+D+3N=36
5N+10D+25*3N=600
4N+D=36
4N=36-D
N=9-D/4
THUS
5(9-D/4)+10D+25*3(9-D/4)=600
45-5D/4+10D+75(9-D/4)=600
45-5D/4+10D+675-75D/4=600
10D-80D/4=600-45-675
(40D-80D)/4=-120
-40D/4=-120
-40D=-480
D=-480/-40
D=12 NUMBER OF DIMES
N+12=3N=36
4N=36-12
4N=24
N=24/4
N=6 NUMBER OF NICKELS
THUS 3N=18 THE NUMBER OF QUARTERS
PROOF
12*10+6*5+18*25=600
120+30+450=600
600=600