SOLUTION: (FLIGHT CONDITIONS) In stable air, the air temperature drops about 5 °(F) for each 1,000-foot rise in altitude. (A) If the temperature at sea level is 100 °F and a commercial pi

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Question 661215: (FLIGHT CONDITIONS) In stable air, the air temperature drops about 5 °(F) for each 1,000-foot rise in altitude.
(A) If the temperature at sea level is 100 °F and a commercial pilot reports a temperature of -30 °F at 26000 feet, write a linear equation that expresses temperature T in terms of altitude A.

Found 2 solutions by josmiceli, lwsshak3:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Plot altitude on the horizontal and temp on the vertical
so, +T+=+f%28A%29+
The slope of the line will be +-5+%2F+1000+ degrees/feet
You are given 2 points on the line,
( 0, 100 ) the sea level temp, and
( 26000, -30 )
--------------
slope = +%28+-30+-+100+%29+%2F+%28+26000+-+0+%29+
slope = +-130+%2F+26000+
slope = -+.005+=+-5%2F1000+
This agrees with the given slope
---------------------------
Using the point-slope formula:
+%28+T+-+100+%29+%2F+%28+A+-+0+%29+=+-.005+
+T+-+100+=+-.005A+
+T+=+-.005A+%2B+100+ answer
check:
does it go through (26000, -30) ?
+T+=+-.005A+%2B+100+
+-30+=+-.005%2A26000+%2B+100+
+-30+=+-130+%2B+100+
+-30+=+-30+
OK
Here's the plot with the horizontal axis expressed
in thousands of feet
+graph%28+400%2C+400%2C+-10%2C+50%2C+-50%2C+200%2C+-5x+%2B+100+%29+


Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
(FLIGHT CONDITIONS) In stable air, the air temperature drops about 5 °(F) for each 1,000-foot rise in altitude.
(A) If the temperature at sea level is 100 °F and a commercial pilot reports a temperature of -30 °F at 26000 feet, write a linear equation that expresses temperature T in terms of altitude A.
**
linear equation takes the form: y=mx+b, m=slope, b=y-intercept
For given problem:
slope=-5º/1000 ft
equation:
T=-5A/1000+b
using coordinates (26000 ft,-30º) of given condition to solve for b
-30=-5*26000/1000+b
-30=-130+b
b=100
equation:
T=-5A/1000+100