SOLUTION: Above, Simone invested $1000 at 8% compounded continuously. In how many years will she have $2000?

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Hi,

A = $1000e^(.08*t) 

$2000 = $1000e^(.08*t)

 2= e^(.08*t)

ln(2) = .08 ln e^t

 ln(2)/.08 = t