SOLUTION: I have also been asked to solve this geometric sequence problem and show the work however I am at a standstill with it. Could you help me with figuring this out, so that I can unde

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Question 609833: I have also been asked to solve this geometric sequence problem and show the work however I am at a standstill with it. Could you help me with figuring this out, so that I can understand how to do this type of work?
A person deposited $500 in a savings account that pays 5% annual interest that is compounded yearly. At the end of 10 years, how much money will be in the savings account?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You can do this the long way without a formula
After 1 year:
+500+%2B+.05%2A500+ in savings account
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After 2 years:
+500+%2B+.05%2A500+%2B+.05%2A%28+500+%2B+.05%2A500+%29+
Here's the trick: factor out +500+%2B+.05%2A500+
+%28+500+%2B+.05%2A500+%29%2A%28+1+%2B+.05+%29%0D%0ANow+factor+out+%7B%7B%7B+500+ from the 1st term:
+500%2A%28+1+%2B+.05+%29%2A%28+1+%2B+.05+%29+
+500%2A%28+1+%2B+.05+%29%5E2+
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After 3 years:
+500%2A%28+1+%2B+.05+%29%5E2+%2B+.05%2A%28+500%2A%28+1+%2B+.05+%29%5E2%29+
Now factor out +500%2A%28+1+%2B+.05+%29%5E2+
+500%2A%28+1+%2B+.05+%29%5E2+%2A%28+1+%2B+.05+%29+
+500%2A%28+1+%2B+.05+%29%5E3+
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As you can see, the formula is +500%2A%28+1+%2B+.05+%29%5En+
where +n+ is the number of years
After +10+ years,
+A+=+500%2A+1.05%5E10+
+log%28+A+%29+=+log%28+500+%29+%2B+10%2Alog%28+1.05+%29+
+log%28+A+%29+=+2.6989+%2B+10%2A.02119+
+log+%28+A+%29+=+2.9108+
+A+=+10%5E2.9108+
+A+=+814.33+
After 10 years, there is $814.33 in the account
check:
+814.33+=+500%2A1.05%5E10+
+814.33%2F500+=+1.05%5E10+
+1.629+=+1.629+
OK