SOLUTION: How do you solve for x log 2x + log(x-5)=2?
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Question 594499
:
How do you solve for x
log 2x + log(x-5)=2?
Answer by
scott8148(6628)
(
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2x(x - 5) = 100
2x^2 - 10x - 100 = 0
x^2 - 5x - 50 = 0
(x + 5)(x - 10) = 0
remember, logarithms are not defined for values ≤0