SOLUTION: Bob paid 3 less than Tim for his lunch at a local pizza parlor. Together they spent $7.80. How much did Bob spend for his lunch?
a. $2.40
b. $4.50
c. $4.80
d. $5.40
e.
Algebra ->
Customizable Word Problem Solvers
-> Finance
-> SOLUTION: Bob paid 3 less than Tim for his lunch at a local pizza parlor. Together they spent $7.80. How much did Bob spend for his lunch?
a. $2.40
b. $4.50
c. $4.80
d. $5.40
e.
Log On
Question 59124: Bob paid 3 less than Tim for his lunch at a local pizza parlor. Together they spent $7.80. How much did Bob spend for his lunch?
a. $2.40
b. $4.50
c. $4.80
d. $5.40
e. $8.40
You can put this solution on YOUR website! Bob paid 3 less than Tim for his lunch at a local pizza parlor. Together they spent $7.80. How much did Bob spend for his lunch?
. $2.40
b. $4.50
c. $4.80
d. $5.40
e. $8.40
:
Let Tim pay:x
Then Bob paid:x-3
Together:7.80
(x)+(x-3)=7.80
2x-3=7.80
2x-3+3=7.80+3
2x=10.80
2x/2=10.80/2
x=5.40
Tim paid: x=$5.40
Bob paid: x-3=$5.40-$3.00=$2.40 (a)
Check, if we add what they paid do we get $7.80?
$5.40+$2.40=$7.80
$7.80=$7.80 Looks good.
Happy Calculating!!!