SOLUTION: I'm having a hard time solving this. I know how to set it up with x+y=43 and .99x+1.25y=49.59 but I'm not sure where to go from there. An online music store sell songs for 2 dif

Question 507949: I'm having a hard time solving this. I know how to set it up with x+y=43 and .99x+1.25y=49.59 but I'm not sure where to go from there.
An online music store sell songs for 2 different prices. Your dad buys you 43 songs for a total of $49.59.
The low cost songs are $0.99 each and the more expensive songs are $1.25 each. How many of each did he
buy?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
An online music store sell songs for 2 different prices. Your dad buys you 43 songs for a total of $49.59.
The low cost songs are $0.99 each and the more expensive songs are $1.25 each. How many of each did he buy?
:
Using your equations
x + y = 43
x = (43-y); we can use this form for substitution
:
.99x + 1.25y = 49.59
from the 1st equation, we can substitute (43-y) for x, solve for y:
.99(43-y) + 1.25y = 49.59
42.57 - .99y + 1.25y = 49.59
-.99y + 1.25y = 49.59 - 42.57
.26y = 7.02
y =
y = 27 ea 1.25 cds
:
I know you can find x, the no. of .99 cds, now. check by finding the total cost
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