SOLUTION: Chris sold small lemonades for $1.29, medium lemonades for $1.49, and large lemonades for $1.85. During a lunch time rush Chris sold 40 lemonades for a total of $59.40. The number
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Question 507088: Chris sold small lemonades for $1.29, medium lemonades for $1.49, and large lemonades for $1.85. During a lunch time rush Chris sold 40 lemonades for a total of $59.40. The number of small and large drinks combined was 10 fewer than the number of medium drinks. How many drinks of each size were sold? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Chris sold small lemonades for $1.29, medium lemonades for $1.49, and large lemonades for $1.85.
During a lunch time rush Chris sold 40 lemonades for a total of $59.40.
The number of small and large drinks combined was 10 fewer than the number of medium drinks.
How many drinks of each size were sold?
;
Let s = no. of small lemonades
let m = no. of med
let b = no. of big lemonades
:
Write an equation for each statement:
:
1.29s + 1.49m + 1.85b = 59.40
:
s + m + b = 40
:
"The number of small and large drinks combined was 10 fewer than the number of medium drinks."
s + b = m - 10
rearrange it to:
s - m + b = -10
:
Use elimination
s + m + b = 40
s - m + b = -10
-------------------subtraction eliminates s and b, find m
2m = 50
m = 25 medium drinks
then
Replace m with 25
s + 25 + b = 40
s + b = 40 - 25
s + b = 15
s = (15-b)
:
1.29s + 1.49m + 1.85b = 59.40
replace s and m
1.29(15-b) + 1.49(25) + 1.85b = 59.40
19.35 - 1.29b + 37.25 + 1.85b = 59.40
-1.29b + 1.85b = 59.40 - 19.35 - 37.25
.56b = 2.80
b =
b = 5 large drinks
then
15 - 5 = 10 small drinks
:
:
Check by adding up the three drinks
10 + 25 + 5 = 40
