Question 466705: A man bought some tools for a total amount of P90,000. If he had bought 50 more tools, it would have cost him P20 less per piece. How many tools did he buy?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! A man bought some tools for a total amount of P90,000. If he had bought 50 more tools, it would have cost him P20 less per piece. How many tools did he buy?
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Let the original number of tools he bought be "x".
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Average cost per tool = 90,000/x
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Average cost if he had bought 50 more would be
90,000/(x+50)
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Equation:
[(90000/x)-(90000/(x+50)] = 20
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90000*50 = 20x(x+50)
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x^2+50x -225000 = 0
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x = 450 (original # of tools purchased)
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Cheers,
Stan H.
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