Question 39238: Saul's father is thinking about buying his son a six-month move pass for $40.00. With the pass, movies cost $1.00. If a movie is normally $3.50 each, how many times would Saul need to attend in order for the pass to be beneficial?
My teacher assigned this problem, and I need to solve it in three (3) different ways. For my first way, I made a chart.
Movies at $1.00 at $3.50
1 $1.00 $3.50
2 $2.00 $7.00
3 $3.00 $10.50
4 $4.00 $14.00
...And so on and so forth. It becomes beneficial at 12 movies, where a regular priced movie would have a running total of $42.00.
My second method was to graph it. I don't need help with that piece.
I cannot think of a third method to solve this problem. Any help would be greatly appriciated.
Answer by longjonsilver(2297)   (Show Source):
You can put this solution on YOUR website! first off, it isn't beneficial at 12 movies.
12 movies: old price = $42 and new price = $12. This is a saving of $30. The ticket cost $40.
You need to look at the DIFFERENCE between the standard and discounted prices.
THIRD METHOD:
Let n= number of movies watched. We need to know when this difference is greater than $40.
So, (3.50-1)n > 40
2.50n > 40
no n > 16
So, at 16 movies, they will break even. Anything above 16 movies and they "save money".
Jon.
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