SOLUTION: if you deposited the following amounts: Type Volume $1 bills = 100 $5 bills = 100 $10 bills = 100 $20 bills = 100 Then your average bill size would be. $9, so how

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: if you deposited the following amounts: Type Volume $1 bills = 100 $5 bills = 100 $10 bills = 100 $20 bills = 100 Then your average bill size would be. $9, so how       Log On

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Question 389131: if you deposited the following
amounts:
Type Volume
$1 bills = 100
$5 bills = 100
$10 bills = 100
$20 bills = 100
Then your average bill size would be. $9, so how was that figured?

Found 2 solutions by richard1234, Edwin McCravy:
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
The total amount of money is

100%2A20+%2B+100%2A10+%2B+100%2A5+%2B+100%2A1. The total number of bills is 400. So the average is

%28100%2A20+%2B+100%2A10+%2B+100%2A5+%2B+100%2A1%29%2F400

=%28100%2820+%2B+10+%2B+5+%2B+1%29%29%2F400

=%2820+%2B+10+%2B+5+%2B+1%29%2F4+=+9

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

   Type   No. of bills     Number of dollars
 $1 bills     100           100×$1 =  $100
 $5 bills     100           100×$5 =  $500
$10 bills     100          100×$10 = $1000
$20 bills     100          100×$20 = $2000
 -------------------------------------------
   Totals     400                    $3600

Average number of dollars per bill is found by dividing

total number of dollars by number of total bills 

              $9          
       400)$3600
            3600
               0

Edwin