SOLUTION: A wallet contains $460 in $5, $10, and $20 bills. The number of $5 bills exceeds twice the number of $10 bills by 4, and the number of $20 bills is 6 fewer than the number of $10 b

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Question 348621: A wallet contains $460 in $5, $10, and $20 bills. The number of $5 bills exceeds twice the number of $10 bills by 4, and the number of $20 bills is 6 fewer than the number of $10 bills.
How many $5 bills?
Found 2 solutions by Fombitz, nyc_function:
Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website!
Let F be the number of $5, T the number of $10, and Y the number of $20 bills.
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"A wallet contains $460 in $5, $10, and $20 bills."
1.
"The number of $5 bills exceeds twice the number of $10 bills by 4"
2.
"the number of $20 bills is 6 fewer than the number of $10 bills."
3.
Substitute eq. 2 and 3 into eq. 1,

Then from eq. 2,

Then from eq. 3,

You have 8 $20 bills, 14 $10 bills, and 32 $5 bills.

Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website!
$5 bills =a

$10 = b

$20 = c

a=2b+4

b-6=c

Since the letters a,b and c represent the number of bills, we have to multiply by their value still since we only know how much money was in the wallet, not how many bills were in there.

5a+10b+20c=460

Now put it all in terms of b

5(2b+4)+10(b)+20(b-6)=460

10b+20+10b+20b-120=460

40b-100=460

40b=560

b=14 (there are 14 $10 bills)

but we want $5 bills and we know how to get there from the number of 10 dollar bills....

a=2b+4

a=2*14+4

a=32

There are 32 $5 bills in the wallet.