SOLUTION: A commonly asked question is, "How long will it take to double my money?" At 10% interest rate and continous compounding, what is the answer?

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Question 33003: A commonly asked question is, "How long will it take to double my money?" At 10% interest rate and continous compounding, what is the answer?

Found 3 solutions by xcentaur, ikleyn, n2:
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
e = 2.71828.
Seems familiar? Its the same as our rate.
+A++=+++P%28e%29%5EYr
That is our final formula.


So we get,
P=10,000
R=2.7183
Years=Y
A=20,000
Continuous compounding:
+A++=+++P%28e%29%5EYr
+20000=10000%28e%29%5EYr
+2+=+%28e%29%5EYr
So log of 2 to the base 'e' is equal to 'Yr'
Log to the base e is also called natural logarithm,or ln()
+Ln%282%29+=+Yr+
+Ln%282%29+=+Y%282.7183%29+
+%28Ln%282%29%29%2F2.7183+=+Y+
Now to convert log to ln we need to multiply by 2.303
+Y+=+%28Ln%282%29%29%2F2.7183+
+Y+=+2.303%2ALog%282%29%2F2.7183+
+Y+=+0.8472%2ALog%282%29+
+Y+=+0.8472%2A0.3010+ (from log tables)
Y=0.255
Obviously,this is a bit small,so adjusting the decimal values we get:
Y=25.5


So to double your money at continous compound rate 'e',
you'd need 25.5 years.


Hope this helps,
xC


Answer by ikleyn(53742) About Me  (Show Source):
You can put this solution on YOUR website!
.
A commonly asked question is, "How long will it take to double my money?" At 10% interest rate and
continuous compounding, what is the answer?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~


        The solution in the post by the other tutor is fatally incorrect.
        I came to bring a correct solution.


The formula for the future value at continuous compounding is 

    FV = A%2Ae%5E%28r%2At%29,    (1).


where A is the deposited amount, 'r' is the nominal interest rate and 't' is the time in years,
'e' is the base of natural logarithms (e = 2.71828...)


In your problem, A = 10,000 dollars,  FV= 20,000 dollars,  r = 0.1.


So, formula (1) takes the form

    20000 = 10000%2Ae%5E%280.1%2At%29.


It implies

    20000%2F10000 = e%5E%280.1%2At%29,

    2 = e%5E%280.1%2At%29.


Take natural logarithm of both sides 

    ln(2) = 0.1*t

    t = ln%282%29%2F0.1 = 6.93147 years.


ANSWEWR.  The time to double the deposited amount is about  6.93 years under given conditions.

Solved correctly with complete explanations.



Answer by n2(78) About Me  (Show Source):
You can put this solution on YOUR website!
.
A commonly asked question is, "How long will it take to double my money?" At 10% interest rate and
continuous compounding, what is the answer?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~


The formula for the future value at continuous compounding is 

    FV = A%2Ae%5E%28r%2At%29,    (1).


where A is the deposited amount, 'r' is the nominal interest rate and 't' is the time in years,
'e' is the base of natural logarithms (e = 2.71828...)


In your problem, A = 10,000 dollars,  FV= 20,000 dollars,  r = 0.1.


So, formula (1) takes the form

    20000 = 10000%2Ae%5E%280.1%2At%29.


It implies

    20000%2F10000 = e%5E%280.1%2At%29,

    2 = e%5E%280.1%2At%29.


Take natural logarithm of both sides 

    ln(2) = 0.1*t

    t = ln%282%29%2F0.1 = 6.93147 years.


ANSWEWR.  The time to double the deposited amount is about  6.93 years under given conditions.