SOLUTION: Can you please help me? I think it's a linear equation. Also, it would help if you put step by step explanations. Thanks so much!!! *A restaurant has fixed costs of $137.50 per da

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: Can you please help me? I think it's a linear equation. Also, it would help if you put step by step explanations. Thanks so much!!! *A restaurant has fixed costs of $137.50 per da      Log On

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Question 30848: Can you please help me? I think it's a linear equation. Also, it would help if you put step by step explanations. Thanks so much!!! *A restaurant has fixed costs of $137.50 per day and an average unit cost of $4.75 for each meal served. If a typical meal costs $6.00, how many customers must eat at the restaurant each day for the owner to make a profit?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
the restaurant's daily income is $6.00 X C where C = number of customers
This must equal or exceed the fixed daily expenses of $137.50 plus
the $4.75/meal served
The equation is
%286.00%29+%2A+C+%3E=+137.50+%2B+4.75+%2A+C
1.25+%2A+C+%3E=+137.50
C+%3E=+137.50%2F1.25
C+%3E=+110
So, there has to be more than 110 cusatomers /day for the
restaurant to make a profit
check
%286.00%29+%2A+110+%3E=+137.50+%2B+4.75+%2A+110
660+=+137.50+%2B+522.50
660+=+660
OK